Integrand size = 24, antiderivative size = 79 \[ \int (1-2 x)^{3/2} (2+3 x)^2 (3+5 x)^3 \, dx=-\frac {65219}{160} (1-2 x)^{5/2}+\frac {20691}{32} (1-2 x)^{7/2}-\frac {21439}{48} (1-2 x)^{9/2}+\frac {28555}{176} (1-2 x)^{11/2}-\frac {975}{32} (1-2 x)^{13/2}+\frac {75}{32} (1-2 x)^{15/2} \]
-65219/160*(1-2*x)^(5/2)+20691/32*(1-2*x)^(7/2)-21439/48*(1-2*x)^(9/2)+285 55/176*(1-2*x)^(11/2)-975/32*(1-2*x)^(13/2)+75/32*(1-2*x)^(15/2)
Time = 0.02 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.48 \[ \int (1-2 x)^{3/2} (2+3 x)^2 (3+5 x)^3 \, dx=-\frac {1}{165} (1-2 x)^{5/2} \left (12136+42860 x+78730 x^2+84225 x^3+49500 x^4+12375 x^5\right ) \]
Time = 0.18 (sec) , antiderivative size = 79, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {99, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int (1-2 x)^{3/2} (3 x+2)^2 (5 x+3)^3 \, dx\) |
\(\Big \downarrow \) 99 |
\(\displaystyle \int \left (-\frac {1125}{32} (1-2 x)^{13/2}+\frac {12675}{32} (1-2 x)^{11/2}-\frac {28555}{16} (1-2 x)^{9/2}+\frac {64317}{16} (1-2 x)^{7/2}-\frac {144837}{32} (1-2 x)^{5/2}+\frac {65219}{32} (1-2 x)^{3/2}\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {75}{32} (1-2 x)^{15/2}-\frac {975}{32} (1-2 x)^{13/2}+\frac {28555}{176} (1-2 x)^{11/2}-\frac {21439}{48} (1-2 x)^{9/2}+\frac {20691}{32} (1-2 x)^{7/2}-\frac {65219}{160} (1-2 x)^{5/2}\) |
(-65219*(1 - 2*x)^(5/2))/160 + (20691*(1 - 2*x)^(7/2))/32 - (21439*(1 - 2* x)^(9/2))/48 + (28555*(1 - 2*x)^(11/2))/176 - (975*(1 - 2*x)^(13/2))/32 + (75*(1 - 2*x)^(15/2))/32
3.19.84.3.1 Defintions of rubi rules used
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_), x_] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] && (IntegerQ[p] | | (GtQ[m, 0] && GeQ[n, -1]))
Time = 0.97 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.44
method | result | size |
gosper | \(-\frac {\left (1-2 x \right )^{\frac {5}{2}} \left (12375 x^{5}+49500 x^{4}+84225 x^{3}+78730 x^{2}+42860 x +12136\right )}{165}\) | \(35\) |
pseudoelliptic | \(-300 \left (x^{5}+4 x^{4}+\frac {1123}{165} x^{3}+\frac {15746}{2475} x^{2}+\frac {8572}{2475} x +\frac {12136}{12375}\right ) \sqrt {1-2 x}\, \left (x -\frac {1}{2}\right )^{2}\) | \(38\) |
trager | \(\left (-300 x^{7}-900 x^{6}-\frac {10085}{11} x^{5}-\frac {5504}{33} x^{4}+\frac {11851}{33} x^{3}+\frac {14722}{55} x^{2}+\frac {5684}{165} x -\frac {12136}{165}\right ) \sqrt {1-2 x}\) | \(44\) |
risch | \(\frac {\left (49500 x^{7}+148500 x^{6}+151275 x^{5}+27520 x^{4}-59255 x^{3}-44166 x^{2}-5684 x +12136\right ) \left (-1+2 x \right )}{165 \sqrt {1-2 x}}\) | \(50\) |
derivativedivides | \(-\frac {65219 \left (1-2 x \right )^{\frac {5}{2}}}{160}+\frac {20691 \left (1-2 x \right )^{\frac {7}{2}}}{32}-\frac {21439 \left (1-2 x \right )^{\frac {9}{2}}}{48}+\frac {28555 \left (1-2 x \right )^{\frac {11}{2}}}{176}-\frac {975 \left (1-2 x \right )^{\frac {13}{2}}}{32}+\frac {75 \left (1-2 x \right )^{\frac {15}{2}}}{32}\) | \(56\) |
default | \(-\frac {65219 \left (1-2 x \right )^{\frac {5}{2}}}{160}+\frac {20691 \left (1-2 x \right )^{\frac {7}{2}}}{32}-\frac {21439 \left (1-2 x \right )^{\frac {9}{2}}}{48}+\frac {28555 \left (1-2 x \right )^{\frac {11}{2}}}{176}-\frac {975 \left (1-2 x \right )^{\frac {13}{2}}}{32}+\frac {75 \left (1-2 x \right )^{\frac {15}{2}}}{32}\) | \(56\) |
meijerg | \(-\frac {81 \left (-\frac {8 \sqrt {\pi }}{15}+\frac {4 \sqrt {\pi }\, \left (8 x^{2}-8 x +2\right ) \sqrt {1-2 x}}{15}\right )}{2 \sqrt {\pi }}+\frac {\frac {864 \sqrt {\pi }}{35}-\frac {108 \sqrt {\pi }\, \left (160 x^{3}-128 x^{2}+8 x +8\right ) \sqrt {1-2 x}}{35}}{\sqrt {\pi }}-\frac {8289 \left (-\frac {64 \sqrt {\pi }}{945}+\frac {4 \sqrt {\pi }\, \left (1120 x^{4}-800 x^{3}+24 x^{2}+16 x +16\right ) \sqrt {1-2 x}}{945}\right )}{32 \sqrt {\pi }}+\frac {\frac {1766 \sqrt {\pi }}{231}-\frac {883 \sqrt {\pi }\, \left (26880 x^{5}-17920 x^{4}+320 x^{3}+192 x^{2}+128 x +128\right ) \sqrt {1-2 x}}{14784}}{\sqrt {\pi }}-\frac {10575 \left (-\frac {1024 \sqrt {\pi }}{45045}+\frac {4 \sqrt {\pi }\, \left (147840 x^{6}-94080 x^{5}+1120 x^{4}+640 x^{3}+384 x^{2}+256 x +256\right ) \sqrt {1-2 x}}{45045}\right )}{128 \sqrt {\pi }}+\frac {\frac {200 \sqrt {\pi }}{1001}-\frac {25 \sqrt {\pi }\, \left (1537536 x^{7}-946176 x^{6}+8064 x^{5}+4480 x^{4}+2560 x^{3}+1536 x^{2}+1024 x +1024\right ) \sqrt {1-2 x}}{128128}}{\sqrt {\pi }}\) | \(275\) |
Time = 0.21 (sec) , antiderivative size = 44, normalized size of antiderivative = 0.56 \[ \int (1-2 x)^{3/2} (2+3 x)^2 (3+5 x)^3 \, dx=-\frac {1}{165} \, {\left (49500 \, x^{7} + 148500 \, x^{6} + 151275 \, x^{5} + 27520 \, x^{4} - 59255 \, x^{3} - 44166 \, x^{2} - 5684 \, x + 12136\right )} \sqrt {-2 \, x + 1} \]
-1/165*(49500*x^7 + 148500*x^6 + 151275*x^5 + 27520*x^4 - 59255*x^3 - 4416 6*x^2 - 5684*x + 12136)*sqrt(-2*x + 1)
Time = 0.80 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.89 \[ \int (1-2 x)^{3/2} (2+3 x)^2 (3+5 x)^3 \, dx=\frac {75 \left (1 - 2 x\right )^{\frac {15}{2}}}{32} - \frac {975 \left (1 - 2 x\right )^{\frac {13}{2}}}{32} + \frac {28555 \left (1 - 2 x\right )^{\frac {11}{2}}}{176} - \frac {21439 \left (1 - 2 x\right )^{\frac {9}{2}}}{48} + \frac {20691 \left (1 - 2 x\right )^{\frac {7}{2}}}{32} - \frac {65219 \left (1 - 2 x\right )^{\frac {5}{2}}}{160} \]
75*(1 - 2*x)**(15/2)/32 - 975*(1 - 2*x)**(13/2)/32 + 28555*(1 - 2*x)**(11/ 2)/176 - 21439*(1 - 2*x)**(9/2)/48 + 20691*(1 - 2*x)**(7/2)/32 - 65219*(1 - 2*x)**(5/2)/160
Time = 0.20 (sec) , antiderivative size = 55, normalized size of antiderivative = 0.70 \[ \int (1-2 x)^{3/2} (2+3 x)^2 (3+5 x)^3 \, dx=\frac {75}{32} \, {\left (-2 \, x + 1\right )}^{\frac {15}{2}} - \frac {975}{32} \, {\left (-2 \, x + 1\right )}^{\frac {13}{2}} + \frac {28555}{176} \, {\left (-2 \, x + 1\right )}^{\frac {11}{2}} - \frac {21439}{48} \, {\left (-2 \, x + 1\right )}^{\frac {9}{2}} + \frac {20691}{32} \, {\left (-2 \, x + 1\right )}^{\frac {7}{2}} - \frac {65219}{160} \, {\left (-2 \, x + 1\right )}^{\frac {5}{2}} \]
75/32*(-2*x + 1)^(15/2) - 975/32*(-2*x + 1)^(13/2) + 28555/176*(-2*x + 1)^ (11/2) - 21439/48*(-2*x + 1)^(9/2) + 20691/32*(-2*x + 1)^(7/2) - 65219/160 *(-2*x + 1)^(5/2)
Time = 0.28 (sec) , antiderivative size = 97, normalized size of antiderivative = 1.23 \[ \int (1-2 x)^{3/2} (2+3 x)^2 (3+5 x)^3 \, dx=-\frac {75}{32} \, {\left (2 \, x - 1\right )}^{7} \sqrt {-2 \, x + 1} - \frac {975}{32} \, {\left (2 \, x - 1\right )}^{6} \sqrt {-2 \, x + 1} - \frac {28555}{176} \, {\left (2 \, x - 1\right )}^{5} \sqrt {-2 \, x + 1} - \frac {21439}{48} \, {\left (2 \, x - 1\right )}^{4} \sqrt {-2 \, x + 1} - \frac {20691}{32} \, {\left (2 \, x - 1\right )}^{3} \sqrt {-2 \, x + 1} - \frac {65219}{160} \, {\left (2 \, x - 1\right )}^{2} \sqrt {-2 \, x + 1} \]
-75/32*(2*x - 1)^7*sqrt(-2*x + 1) - 975/32*(2*x - 1)^6*sqrt(-2*x + 1) - 28 555/176*(2*x - 1)^5*sqrt(-2*x + 1) - 21439/48*(2*x - 1)^4*sqrt(-2*x + 1) - 20691/32*(2*x - 1)^3*sqrt(-2*x + 1) - 65219/160*(2*x - 1)^2*sqrt(-2*x + 1 )
Time = 0.03 (sec) , antiderivative size = 55, normalized size of antiderivative = 0.70 \[ \int (1-2 x)^{3/2} (2+3 x)^2 (3+5 x)^3 \, dx=\frac {20691\,{\left (1-2\,x\right )}^{7/2}}{32}-\frac {65219\,{\left (1-2\,x\right )}^{5/2}}{160}-\frac {21439\,{\left (1-2\,x\right )}^{9/2}}{48}+\frac {28555\,{\left (1-2\,x\right )}^{11/2}}{176}-\frac {975\,{\left (1-2\,x\right )}^{13/2}}{32}+\frac {75\,{\left (1-2\,x\right )}^{15/2}}{32} \]